(3n^2+4n)+(n^2+n)=

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Solution for (3n^2+4n)+(n^2+n)= equation:


Simplifying
(3n2 + 4n) + (n2 + n) = 0

Reorder the terms:
(4n + 3n2) + (n2 + n) = 0

Remove parenthesis around (4n + 3n2)
4n + 3n2 + (n2 + n) = 0

Reorder the terms:
4n + 3n2 + (n + n2) = 0

Remove parenthesis around (n + n2)
4n + 3n2 + n + n2 = 0

Reorder the terms:
4n + n + 3n2 + n2 = 0

Combine like terms: 4n + n = 5n
5n + 3n2 + n2 = 0

Combine like terms: 3n2 + n2 = 4n2
5n + 4n2 = 0

Solving
5n + 4n2 = 0

Solving for variable 'n'.

Factor out the Greatest Common Factor (GCF), 'n'.
n(5 + 4n) = 0

Subproblem 1

Set the factor 'n' equal to zero and attempt to solve: Simplifying n = 0 Solving n = 0 Move all terms containing n to the left, all other terms to the right. Simplifying n = 0

Subproblem 2

Set the factor '(5 + 4n)' equal to zero and attempt to solve: Simplifying 5 + 4n = 0 Solving 5 + 4n = 0 Move all terms containing n to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 4n = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 4n = 0 + -5 4n = 0 + -5 Combine like terms: 0 + -5 = -5 4n = -5 Divide each side by '4'. n = -1.25 Simplifying n = -1.25

Solution

n = {0, -1.25}

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